Solve Equations using a Matrix

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Homework Help Overview

The discussion revolves around solving a system of linear equations using matrix methods. The original poster presents a set of equations and their corresponding augmented matrix, detailing their steps in row reduction and substitution to find the values of the variables.

Discussion Character

  • Mathematical reasoning, Problem interpretation, Assumption checking

Approaches and Questions Raised

  • Participants discuss the construction of the matrix equation and the validity of the row operations performed. There are questions about the correctness of the solutions derived from the matrix and whether the original equations are satisfied.

Discussion Status

Some participants affirm the correctness of the augmented matrix and the final values obtained for the variables. Others suggest verifying the solutions by substituting them back into the original equations. There is acknowledgment of a misunderstanding regarding the substitution process by the original poster.

Contextual Notes

There is a mention of differing results when using subtraction methods, indicating potential confusion or missteps in the approach taken by the original poster.

2slowtogofast
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solve equations using a matrix

x + y -z = 0
3x - y + z = 4
5x +z = 7

so i wrote the matrix

1 1 -1 0
3 -1 1 4
5 0 1 7

then i multiplied Row 1 by -3 and added that to row 2
and multiplied row 1 by -5 and added that to row 3
resulting in

1 1 -1 0
0 -4 4 4
0 -5 6 7

then i multiplied row 2 by - 1/4

1 1 -1 0
0 1 -1 -1
0 -5 6 7

then multiplied row 2 by 5 and added that to row 3

1 1 -1 0
0 1 -1 -1
0 0 1 2

now i subbed back into eqns

x + y -z = 0
3x - y + z = 4
5x +z = 7

1x + 1y - 1z = 0
0x +1y - 1z = -1
0x + 0y + 1z = 2

so z = 2 and solving all the other equation i get x = 1 and y = 1
is this right because i tried solving these by subtraction and got somthing different
 
Last edited:
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You have not constructed a matrix equation, you have just rewritten the coefficients in some kind of array/pattern

THe matrix equation is :

[tex]\begin{pmatrix}<br /> 1 & 1 & -1\\<br /> 3&-1 & 1\\<br /> 5&0&1<br /> \end{pmatrix}<br /> \begin{pmatrix}<br /> x\\<br /> y\\<br /> z<br /> \end{pmatrix}<br /> =<br /> \begin{pmatrix}<br /> 0\\<br /> 4\\<br /> 7<br /> \end{pmatrix}<br /> [/tex]
 
Last edited:
The augmented matrix that 2slow to go fast used is correct.
All you need to do is plug x y and z back into your original equations and see if they make true statements.
Looks to me like they check out.
CC
 
i just got it i was substituting wrong thanks for the help
 

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