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[Onewayz]

Hello, could someone please solve this for me?
Or try and help me at least...
FD = 1/4 AV^2 / FD=(1/2)pv2AC

 

[mikeph]

What do you want it solved for? I don't even understand the equation(s), please use more brackets to make the division clearer.

 

[bhillyard]

This needs some context.
Are FD and AC single items or the product of F & D, A & C respectively? Similarly for AV & pv.
What unknown are you trying to solve for?

 

[technician]

If the second part is written as
FD = 0.5ρACv² it is an expression to calculate friction drag (FD?) through air.
A is the cross section area, C is a drag coefficient, ρ = density of fluid (air for example)

 

[256bits]

Another thread on drag force, several more with a search, which is what the equations seem to imply.

https://www.physicsforums.com/showthread.php?t=342546

FD = 1/4 AV^2 is an approxiamation.

 

[Onewayz]

Yes , it is indeed to calculate the friction drag through the air, but i want to know the answer, kind of.
Have been trying to solve this for a long period of time and can't stop thinking about it.

 

[physwizard]

lol haven't u heard of lateX?