Solve for Initial Speed: Inelastic Collisions with Ballistic Pendulum

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SUMMARY

The discussion focuses on calculating the initial speed of a bullet that strikes a ballistic pendulum, where the bullet has a mass of 6 g and the pendulum has a mass of 2.0 kg. The pendulum rises a vertical distance of 14 cm after the collision, resulting in a potential energy increase of 2.755 J. Using the kinetic energy formula, the initial speed of the bullet is determined to be 30.3 m/s. It is noted that conservation of energy principles do not apply in this inelastic collision scenario.

PREREQUISITES
  • Understanding of kinetic energy (KE = 1/2 mv²)
  • Knowledge of potential energy (P.E. = mgh)
  • Familiarity with inelastic collisions
  • Basic principles of conservation of momentum
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  • Learn about conservation of momentum in collision scenarios
  • Explore the concept of ballistic pendulums and their applications
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Homework Statement



A bullet of mass 6 g strikes a ballistic pendulum of mass 2.0 kg. The center of mass of the pendulum rises a vertical distance of 14 cm. Assuming that the bullet remains embedded in the pendulum, calculate the bullet's initial speed.

Homework Equations



KE=1/2(mv^2)

3. The Attempt at a Solution [/b
The entire mass of pendulum & bullet rises 0.14 m,
this is a P.E. change of mgh (where m = 2.006 kg, h = 0.14 m)
P.E.(increase) = 2.006(9.81)(0.14) = 2.755 J
The initial K.E. of the bullet must equal this increase
1/2 mv² = 2.755
mv² = 5.510
v² = 5.510/0.006)
v² = 918.3
v = 30.3 m/s ANS
 
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Conservation of energy is not valid for inelastic collision.

ehild
 

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