Solve for x: 4^(x-5) = 7^(2x-1) | Equation Help

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SUMMARY

The equation \(4^{(x-5)} = 7^{(2x-1)}\) can be solved by applying logarithmic properties. By taking the logarithm of both sides, the equation simplifies to \((x-5) \log 4 = (2x-1) \log 7\). This transformation is based on the logarithmic identity \(\log a^x = x \log a\). The solution involves isolating \(x\) in this linear equation format.

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Nikolas7
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Help me with the following equation:
${4}^{x-5}$=${7}^{2x-1}$
 
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Nikolas7 said:
Help me with the following equation:
${4}^{x-5}$=${7}^{2x-1}$

you can take log on both sides and get $(x-5)\log\, 4 = (2x-1) log\, 7$ and because it is linear equation you can proceed to finish it
 
Please, show details how you got (x−5)log4=(2x−1)log7
 
Nikolas7 said:
Please, show details how you got (x−5)log4=(2x−1)log7

this is as per definition $\log\,a ^ x = x \log\, a $
 
Yes, I figured out, thanks
 

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