Solve Kinematics Problem: Rocket Powered Sledge Speed in 60m Section

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Homework Help Overview

The problem involves a rocket-powered sledge that accelerates through a 60m section of a test track with a given acceleration. Participants are tasked with finding the initial and final speeds of the sledge based on the provided parameters.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the use of kinematic equations, particularly focusing on rearranging the equation x = ut + 1/2at² to solve for initial speed (u) and final speed (v). Some express confusion about their calculations and the correctness of their methods.

Discussion Status

There is an ongoing exploration of different methods to solve the problem, with participants questioning their calculations and the rearrangement of equations. Some guidance has been offered regarding potential errors in transposition, and participants are encouraged to share their workings for further clarification.

Contextual Notes

Participants mention discrepancies between their results and those suggested by a teacher, indicating uncertainty about the correct approach or calculations. There is a focus on understanding the equations rather than simply arriving at a solution.

ella_101
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Homework Statement



A rocket powered sledge accelerates at 35ms-2 and takes 1.6s to pass through a 60m section of a test track. Find the speed at which it entered the section what was its speed when it left?

Homework Equations



I think this is the equation to use x=ut + 1/2at2 and than use a=v-u/t to get v ?


The Attempt at a Solution



a= 35m/s
t= 1.6s
u=?
v=?
x= 60m

I got weird answers so there's no point putting them up!

please show your working

thanks
 
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ella_101 said:

Homework Statement



A rocket powered sledge accelerates at 35ms-2 and takes 1.6s to pass through a 60m section of a test track. Find the speed at which it entered the section what was its speed when it left?

Homework Equations



I think this is the equation to use x=ut + 1/2at2 and than use a=v-u/t to get v ?


The Attempt at a Solution



a= 35m/s
t= 1.6s
u=?
v=?
x= 60m

I got weird answers so there's no point putting them up!

please show your working

thanks

What exactly do you mean by a weird answer? Please put workings up, because your method seems right.
 
when i make 'u' the subject of the forumal i got 65.5 ( which is wrong) and for 'v' I got 121.5

I think my teacher said the answer was 9.5 for u and v i don't know,

what did you get ?
 
I know its an 'easy' question but i think i am just getting the equation wrong
 
ella_101 said:
when i make 'u' the subject of the forumal i got 65.5 ( which is wrong) and for 'v' I got 121.5

I think my teacher said the answer was 9.5 for u and v i don't know,

what did you get ?

Teacher is right, just remember that experience is the best teacher so by making this mistake and figuring out where you made it you've learned more, than me simply showing you the solution.

If you want you can show me you workings step by step, but as far as I can tell your eq is right your just calculating it incorrectly.How did you get 65.5?
 
okay,

x= ut + 1/2 at2

rearranged to give;

u= 1/2at2 + x/t ( this is were I think I am going wrong , rearranging it?)

than just plug in the numbers. = 65.5

OR
alternatively you can 'show' your working out=)
 
Alternatively, I found you can use simultaneous equations:
(v+u)/2=s/t...So, v+u=75 (i)
Also, v=u+at...So, u=v-56 (ii)
Now, we have 2v-56=75, and v=65.5...u=9.5
That's a simpler, but more bothersome method...
 
Last edited:
Your transposition is a little faulty... If s=ut+1/2at^2...Then u = (s-1/2at^2)/t...What you found was your final velocity, v...Since, s=vt-1/2at^2...v=(s+1/2at^2)/t...Go back over your steps in rearranging the equation, you'll see the mistake.
 
Last edited:

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