Solve ln(a/b+1) Using Identity ln(a+b)=ln b + ln(a/b+1)
- Context: Undergrad
- Thread starter Gurasees
- Start date
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- Tags
- Logarithm
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Discussion Overview
The discussion revolves around the expression "ln(a/b+1)" and its manipulation using the identity "ln(a+b)=ln b + ln(a/b+1)". Participants explore the implications of this identity, particularly in the context of a specific expression involving temperature (T) and logarithmic functions. The scope includes mathematical reasoning and potential numerical solutions.
Discussion Character
- Technical explanation
- Mathematical reasoning
- Debate/contested
Main Points Raised
- One participant questions the meaning of "solve" in relation to the expression, suggesting that the identity leads to repetitive forms.
- Another participant presents a specific logarithmic expression involving temperature and suggests numerical methods or power series expansion as potential approaches.
- Several participants express uncertainty about how to simplify or solve the expression further without a specific equation.
- There are repeated requests for resources or links to help with understanding power series related to logarithmic and exponential functions.
- One participant emphasizes the importance of considering the interval of convergence when expanding functions into series.
- Another participant asks about the expansion of ln(x-a) and requests assistance in finding it.
Areas of Agreement / Disagreement
Participants generally agree that the expression cannot be simplified further without an equation. However, there is no consensus on how to approach the problem or what constitutes a solution, leading to multiple competing views on the methods to be used.
Contextual Notes
Participants note the dependence on the variable T and the importance of understanding the range of T-292 for the power series to be applicable. There is also mention of the need for an actual equation to facilitate solving the problem.
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