Solve Math Problem: (8sq*7x)-2(3+4x)

[jd0011]

I was wondering if i had a question like (2squared+3) would i go 2*2+3= 7

If i had (8sq*7x)-2(3+4x)

how do i expand and simply also work out i don't understand how to work this out and what i need to do fisrt ?

would i go 8*8 = 64 +7 = 71 -2 =69 +3+4 =75sq x ? or is this wrong

 

[ideasrule]

I was wondering if i had a question like (2squared+3) would i go 2*2+3= 7

Is it 2^2+3? If so, the answer is indeed 7.

If i had (8sq*7x)-2(3+4x)
how do i expand and simply also work out i don't understand how to work this out and what i need to do fisrt ?

I don't understand. What are you trying to work out? If you want to simplify, it's:

8^2*7x - 2(3+4x)
=448x-6-8x
=440x-6

 

[jd0011]

8^2*7x - 2(3+4x)
=448x-6-8x
=440x-6

So that is how i simplify

how did you get 6-8 from the eqaution ?

 

[HallsofIvy]

I was wondering if i had a question like (2squared+3) would i go 2*2+3= 7

If i had (8sq*7x)-2(3+4x)

how do i expand and simply also work out i don't understand how to work this out and what i need to do fisrt ?

would i go 8*8 = 64 +7 = 71 -2 =69 +3+4 =75sq x ? or is this wrong

What you wrote was 8sq 7 x which appears to mean 8^2 times 7. Did you mean to write 8^2+7x? If so then it is 64+ 7x not (8^2+ 7)x which would be 81x.