Solve Momentum & Impulse Homework: Diver Leaves Raft at 4 m/s

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SUMMARY

The problem involves a 75 kg swimmer diving off a 300 kg raft, with the raft moving at 1.0 m/s after the dive. Using the conservation of momentum principle, the initial momentum of the system (swimmer + raft) is equal to the final momentum. The correct speed at which the diver leaves the raft is calculated to be 4 m/s, confirmed through the equation p=mv and the momentum conservation formula M1v1 + m2v2 = m1v1' + m2v2'.

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Homework Statement



18. A 75 kg swimmer dives horizontally off a 300 kg raft. If the speed of the raft immediately after the swimmer dives off is 1.0 m/s, at what speed did the diver leave the raft?

A. 2 m/s B. 4 m/s C. 6 m/s D. 8 m/s E. 10 m/s


Homework Equations



p=mv

The Attempt at a Solution


I can't figure out how to use the equation to solve the problem. The only answer that I could find was 4 m/s and I did that by taking 300/75. Can somebody work it out step-by-step for me please?
 
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If swimmer and raft are initially at rest, what is the initial momentum of (swimmer + raft)?
 
Conservation of momentum in the x direction may help you. M1v1 + m2v2 = m1v1' + m2v2'

The ' symbol means prime. The equation represents momentum of two objects before the collision is the same as the momentum of two objects after
 

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