Solve Selective Reduction of Sn4+ to Sn2+ w/o Sn2+ to Sn

  • Thread starter Thread starter higherme
  • Start date Start date
  • Tags Tags
    Reduction
Click For Summary
SUMMARY

The discussion focuses on determining the appropriate anodic half-reaction that allows for the spontaneous reduction of Sn4+ to Sn2+ without facilitating the reverse reaction of Sn2+ to Sn. The calculated oxidation potentials for the reactions Pb --> Pb2+, Sn2+ --> Sn4+, and Fe --> Fe3+ indicate that these reactions yield a positive Ecell, confirming their suitability for the desired reduction. The participant questions whether an Ecell of zero indicates spontaneity, which is clarified as being non-spontaneous under standard conditions.

PREREQUISITES
  • Understanding of standard reduction potentials in electrochemistry
  • Familiarity with galvanic cell reactions
  • Knowledge of half-reaction notation and calculations
  • Ability to interpret Ecell values for spontaneity
NEXT STEPS
  • Study the Nernst equation for non-standard conditions
  • Learn about the implications of Ecell = 0 in electrochemical systems
  • Explore the concept of equilibrium in redox reactions
  • Investigate selective oxidation and reduction processes in electrochemistry
USEFUL FOR

Chemistry students, electrochemists, and anyone studying redox reactions and galvanic cells will benefit from this discussion.

higherme
Messages
126
Reaction score
0

Homework Statement



Given: Sn4+ + 2e- --->Sn2+ Estandard=+0.15V
For a galvanic cell under standard condition, which of the following anodic half reaction would produce at the cathode a spontaneous reduction of Sn4+ to Sn2+ but NOT Sn2+ to Sn.

Pb --> Pb2+ + 2e-
Sn2+ --> Sn4+ + 2e-
Pb + SO42- --> PbSO4 + 2e-
Sn --> Sn2+ + 2e-
Fe --> Fe3+ + 3e-
Ni --> Ni2+ + 2e-

The Attempt at a Solution



I found the oxidation potential for all of the above reactions:

+0.126
-0.139
+0.355
+0.141
+0.036
+0.236, respectively

For a spontaneous reaction, the Ecell has to be positive. I calculated the Ecell for each of those reactions with Sn4+ + 2e- --->Sn2+ Estandard=+0.15V and with Sn2+ + 2e---->Sn

I found that Pb --> Pb2+ + 2e-, Sn2+ --> Sn4+ + 2e-, and Fe --> Fe3+ + 3e- are the only three that produce a Ecell that is positive for Sn4+ to Sn2+ and NOT Sn2+ to Sn

but for Sn --> Sn2+ + 2e- reacting with Sn2+ + 2e---->Sn, the Ecell is obviously equation to zero, would that considered to be spontaneous??

can someone check if I am doing this right?

Thanks a lot =)
 
Physics news on Phys.org
am I on the right track here?
 
do u go to the UoW? :)
 
what is "UoW"?
 
lol i guess not


by the way in ur questions do u have one like this..

Selective Oxidation (not reduction)

--------------------------------------------------------------------------------

1. The standard reduction potential for the half-reaction

Sn4+ + 2e- Sn2+
is +0.15 V.
Consider data from the table of standard reduction potentials for common half-reactions, in your text.

For a galvanic cell under standard conditions, which of the following cathodic half reactions would produce, at the anode, a spontaneous oxidation of Sn to Sn2+ but not Sn2+ to Sn4+.

Sn2+ + 2e- Sn
Pb2+ + 2e- Pb
2H2O + 2e- H2 + 2OH-
PbSO4 + 2e- Pb + SO42-
Fe2+ + 2e- Fe
Fe3+ + 3e- Fe
 
yeah, something similar to that.
 
can someone please check what I'm doing wrong here... I'm still not getting the correct answer =(
 
if the Ecell = 0 (in equilibrium) is that still considered to be spontaneous?
 

Similar threads

  • · Replies 6 ·
Replies
6
Views
9K