Solving Selective Oxidation with Standard Reduction Potential

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Discussion Overview

The discussion revolves around solving a problem related to standard reduction potentials in the context of galvanic cells. Participants are tasked with identifying which cathodic half-reactions would allow for the spontaneous oxidation of Sn to Sn2+ without further oxidation to Sn4+. The scope includes theoretical reasoning and application of electrochemical principles.

Discussion Character

  • Homework-related, Mathematical reasoning, Technical explanation

Main Points Raised

  • One participant states the standard reduction potential for the half-reaction Sn4+ + 2e- → Sn2+ is +0.15 V.
  • Another participant expresses confusion about the problem and suggests looking at standard potentials.
  • A different participant analyzes the given half-reactions and their potentials, noting that Sn2+ + 2e- → Sn has a potential of -0.13 V and questions its spontaneity.
  • One participant argues that the reaction Pb2+ + 2e- → Pb is spontaneous and would occur at the cathode, allowing Sn to be oxidized to Sn2+.
  • Another participant evaluates the half-reaction 2H2O + 2e- → H2 + 2OH- and concludes it would occur at the anode due to its more negative potential.
  • Further analysis includes the half-reaction PbSO4 + 2e- → Pb + SO42- and Fe2+ + 2e- → Fe, both deemed non-spontaneous for the desired oxidation.
  • One participant concludes that Fe3+ + 3e- → Fe would allow for the oxidation of Sn to Sn2+ since it has a lower potential and is spontaneous.
  • Several participants express urgency and seek confirmation on their reasoning before submitting their assignment.

Areas of Agreement / Disagreement

Participants express varying levels of confidence in their interpretations of the standard reduction potentials and their implications for the problem. There is no consensus on the correct cathodic half-reaction, and multiple competing views remain regarding the spontaneity of the reactions.

Contextual Notes

Participants reference specific standard reduction potentials but do not provide a complete analysis of all assumptions or dependencies on definitions. The discussion reflects uncertainty regarding the interpretation of the problem and the application of electrochemical principles.

salman213
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1. The standard reduction potential for the half-reaction

Sn4+ + 2e- Sn2+
is +0.15 V.
Consider data from the table of standard reduction potentials for common half-reactions, in your text.

For a galvanic cell under standard conditions, which of the following cathodic half reactions would produce, at the anode, a spontaneous oxidation of Sn to Sn2+ but not Sn2+ to Sn4+.

Sn2+ + 2e- Sn
Pb2+ + 2e- Pb
2H2O + 2e- H2 + 2OH-
PbSO4 + 2e- Pb + SO42-
Fe2+ + 2e- Fe
Fe3+ + 3e- Fe



HOW DO I APPROACH THIS PROBLEM?
 
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any help >
 
Well what are your thoughts on the problem. Also it seems kind of obvious from your choices think about it..
 
Im not really sure how to approach this , i gues i have to look at standard potentials but I am not sure what the question is asking me.
 
Ok I am confused this is wat i did
Sn4+ + 2e- Sn2+
is +0.15 V.

For a galvanic cell under standard conditions, which of the following cathodic half reactions would produce, at the anode, a spontaneous oxidation of Sn to Sn2+ but not Sn2+ to Sn4+.
Sn2+(aq) + 2e− → Sn(s) −0.13

Sn2+ + 2e- Sn -0.13 V
No not spontaeous this is at equilibirum?

Pb2+ + 2e- Pb 0.13 V
Yes because it is spontaneous and the Sn2+ to Sn4+ will occur at the cathode

2H2O + 2e- H2 + 2OH- -0.828 V
No because this will occur at anode since more negative

PbSO4 + 2e- Pb + SO42- -0.359 V
No because this will occur at anode since more negative

Fe2+ + 2e- Fe −0.44 V
No because this will occur at anode since more negative

Fe3+ + 3e- Fe -0.04 V
Yes the Sn will be oxidized to Sn2+ since it has lower potential -.13 and it is spontaneous and also the Sn2+ to Sn4+ will not happen at anode since it is much more positive.


I ONLY HAVE 1 MORE TRY TO GET IT RIGHT ON MY ASSIGNMENT ONLINE PLZ HELPPPPPPPPPPPPPPP
 
Last edited:
I think these are right but I don't want to submit them before making sure with someone smart at this forum since i only have one chance left... lol :)

please anyone check!
 
I got it
 
Last edited:

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