Solve sin(t) cos(2t)=b1 sin(t)+b2 sin(2t)+b3 sin(3t)

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Homework Help Overview

The discussion revolves around the equation sin(t) cos(2t) = b1 sin(t) + b2 sin(2t) + b3 sin(3t), where the original poster seeks to determine the coefficients b1, b2, and b3. The subject area involves trigonometric identities and their applications in solving equations.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster expresses uncertainty about how to find the coefficients and mentions an attempt to convert the expression to complex form, which did not yield helpful results. Some participants suggest using product-to-sum identities to facilitate the conversion of the left side of the equation into a form that can be compared to the right side.

Discussion Status

Participants are exploring different methods to approach the problem, with some suggesting specific identities that could be useful. There is an acknowledgment of shared resources, indicating a collaborative effort to clarify the problem without reaching a consensus on a single method yet.

Contextual Notes

The original poster appears to be working under constraints typical of homework assignments, which may limit the resources they can use or the methods they can apply. There is an implicit assumption that the use of trigonometric identities is appropriate for this problem.

aqsa
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sin(t) cos(2t) = ??

ok so i have to find the values for b1,b2 and b3...but i am clueless on how to find them
can anyone help?

sin(t) cos(2t) = b1 sin(t) + b2 sin(2t) + b3 sin(3t):

i thought of converting it to complex but that did not help much!
 
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o yeah..forgot about those! thanks guys!
 

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