Solve the follow diferential equation

  • Context: Graduate 
  • Thread starter Thread starter alejandrito29
  • Start date Start date
Click For Summary

Discussion Overview

The discussion revolves around solving a differential equation of the form (\frac{du}{dy})^2=A+Be^{2u}+C \sqrt{D+Ee^{4u}}, where A, B, C, D, and E are nonzero constants. The context includes both academic and research applications.

Discussion Character

  • Homework-related
  • Technical explanation
  • Exploratory

Main Points Raised

  • One participant seeks to solve the differential equation and inquires about its context, asking if it is for schoolwork.
  • Another participant clarifies that the question is related to their thesis work and mentions previous attempts to solve it.
  • A participant provides an implicit solution derived from Maple, presenting it in integral form and noting the presence of an arbitrary constant.
  • There is a suggestion that separation of variables is an obvious method, but a participant questions whether an explicit solution can be found.
  • Another participant proposes a substitution method, suggesting z=e^{2\zeta} and relating it to hyperbolic functions, while noting that the resulting expression is complex.
  • Further clarification on the substitution is provided, questioning if 2\zeta=ln(\sqrt(D/E)sinh(\theta)) is correct.

Areas of Agreement / Disagreement

Participants express various approaches to solving the differential equation, but there is no consensus on the best method or whether an explicit solution is achievable.

Contextual Notes

The discussion includes unresolved mathematical steps and assumptions related to the methods proposed for solving the differential equation.

alejandrito29
Messages
148
Reaction score
0
i need to solve the follow diferential equation:

[tex](\frac{du}{dy})^2=A+Be^{2u}+C \sqrt{D+Ee^{4u}}[/tex]

where A,B,C,D,E are nonzero.
 
Physics news on Phys.org


alejandrito29 said:
i need to solve the follow diferential equation:

[tex](\frac{du}{dy})^2=A+Be^{2u}+C \sqrt{D+Ee^{4u}}[/tex]

where A,B,C,D,E are nonzero.

What is the context of the question? Is it for schoolwork?
 


berkeman said:
What is the context of the question? Is it for schoolwork?

not, is for my thesis. I have tried make him.
 


Maple gives the following solution to your ODE (in implicit form)

[tex]\int_k^{u(y)}\frac{d\xi}{\sqrt{A+Be^{2\xi}+C\sqrt{D+Ee^{4\xi}}}}=\pm y,[/tex]

where k is an arbitrary constant.
 


kosovtsov said:
Maple gives the following solution to your ODE (in implicit form)

[tex]\int_k^{u(y)}\frac{d\xi}{\sqrt{A+Be^{2\xi}+C\sqrt{D+Ee^{4\xi}}}}=\pm y,[/tex]

where k is an arbitrary constant.

obvious, separation variables, but

there is a way to find a explicit solution?
 


Try [tex]z=e^{2\zeta}[/tex], then [tex]z=\sqrt(D/E)Sinh(\theta)[/tex]. Maple manages to integrate that, but the resulting expression is nasty
 


gato_ said:
Try [tex]z=e^{2\zeta}[/tex], then [tex]z=\sqrt(D/E)Sinh(\theta)[/tex]. Maple manages to integrate that, but the resulting expression is nasty

[tex]2\zeta=ln(\sqrt(D/E)sinh(\theta))?[/tex]
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
2K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
7K
  • · Replies 2 ·
Replies
2
Views
4K
  • · Replies 18 ·
Replies
18
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 12 ·
Replies
12
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K