Solve Time to Pull Illinois Jones from Pit

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SUMMARY

The discussion focuses on calculating the minimum time required to pull Illinois Jones from a 3.9 m deep snake pit using a rope that breaks under a tension exceeding 725 N. The participant initially calculated the acceleration using the formula F=ma, resulting in an acceleration of 11.69 m/s², which raised concerns about its validity. The tension in the rope is not the sole force acting on Illinois Jones; gravitational force must also be considered in the net force calculation to determine the correct acceleration and subsequently the time to pull him out.

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Illinois Jones is being pulled from a snake pit with a rope that breaks if the tension in it exceeds 725 N. If Illinois Jones has a mass of 62 kg and the snake pit is 3.9 m deep, what is the minimum time necessary to pull our intrepid explorer from the pit?



F=ma and a=d/t^2



I put in 725 for the force so I had 725=(62kg)(a) and that gave me 11.69 for a, but that doesn't really make sense. That may be right but seems like an insanely high acceleration. Was I wrong in doing that?
 
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The acceleration is produced by the net force. The tension in the rope is not the only force acting on him.
 

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