Solve Trig Question: cot(Arctan (-√(5)/2))

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SUMMARY

The discussion focuses on solving the trigonometric expression cot(Arctan(-√(5)/2)). It establishes that cot(x) is the reciprocal of tan(x), leading to the conclusion that cot(Arctan(-√(5)/2)) equals 1/tan(Arctan(-√(5)/2)). The value of tan(Arctan(-√(5)/2)) is directly -√(5)/2, thus simplifying the expression to -2/√5.

PREREQUISITES
  • Understanding of trigonometric functions, specifically cotangent and tangent.
  • Familiarity with the concept of inverse trigonometric functions, particularly Arctan.
  • Knowledge of basic algebraic manipulation and simplification.
  • Ability to interpret values on the unit circle.
NEXT STEPS
  • Study the properties of inverse trigonometric functions, focusing on Arctan.
  • Learn how to derive cotangent values from tangent expressions.
  • Explore the unit circle and its application in solving trigonometric identities.
  • Practice additional problems involving cotangent and inverse functions for proficiency.
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Students studying trigonometry, educators teaching trigonometric identities, and anyone seeking to improve their problem-solving skills in trigonometric equations.

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Homework Statement


How do I solve this trig question?
cot(Arctan (-√(5)/2))

Homework Equations


The usual equation I know of which is easy o identify on the Unit circle is √3/2. I don't know how to approach this one..


The Attempt at a Solution


 
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You do know that cot(x)= 1/tan(x) don't you? So cot(Arctan (-√(5)/2))= 1/tan(Arctan (-√(5)/2)).

And what do you think tan(Arctan (-√(5)/2)) is?
 
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