Solve Work Formula Problem: Calculate Force Exerted by Man

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SUMMARY

The discussion centers on calculating the force exerted by a man pushing against a 330 kg piano sliding down a 28-degree incline, with an effective coefficient of kinetic friction of 0.40. The correct formula to determine the force exerted by the man is F = mgsin(theta), which yields a force of 3237.3 N. However, the calculation must also account for the force of friction opposing the motion, which is essential for an accurate assessment of the total force required to keep the piano stationary on the incline.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Knowledge of trigonometric functions, particularly sine
  • Familiarity with the concept of friction and its coefficients
  • Basic skills in algebra for manipulating equations
NEXT STEPS
  • Calculate the force of friction using the formula F_friction = μ * N, where N is the normal force.
  • Learn how to resolve forces on inclined planes in physics.
  • Study the implications of static vs. kinetic friction in real-world applications.
  • Explore advanced topics in dynamics, such as net force and acceleration analysis.
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in understanding force calculations in mechanics, particularly in scenarios involving friction and inclined planes.

Farm4Life
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I have pretty much figured out the problem, but i am unsure of my work.
the question reads:
a 330kg piano slides 3.6m down a 28degree incline and is kept from accelerating by a man who is pushing back on it parallel to the incline. The effective coefficient of kinetic friction is 0.40. Calculate: (a) the force exerted by the man.

F=mgsin(theta)
=(330kg)(9.81m/s2)sin90
F= 3237.3 N

Is this the correct formula to use to find the force exerted by the man?
 
Physics news on Phys.org
Where is the force due to the friction? The man's job is made easier by the help of friction.
 

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