Solving 121 sinθ cosθ + 592.9 cos²θ = 1

[hayowazzup]

Homework Statement

1 = 121 sinθ *cosθ + 592.9 (cos²θ)

Homework Equations

The Attempt at a Solution

1= 60.5 * 2 *sin θ *cosθ + 592.9 (cos²θ)
1= 60.5 sin 2θ + 592.9 (cos²θ)
1-60.5 sin 2θ / cos θ cos θ= 592.9

am i doing it rite? i don't know what to do

 

[dirk_mec1]

Use $$sin^2 + cos^2 =1$$

 

[hayowazzup]

but i don't know how to get rid of sin θ *cosθ

 

[Dick]

You wrote sin(theta)*cos(theta) in terms of sin(2*theta). Write cos(theta)^2 in terms of cos(2*theta).