Solving 2nd Order Non-Homogeneous DE with Variables: A Comprehensive Guide

[Peregrine]

I am familiar with how to solve a second order, non-homogenous DE with constants, i.e.

\frac {\partial^2X(t)}{\partial t^2} + \frac{\partial X(t)}{\partial t} = C

by first solving the homogenous eqn, then setting the equation equal to a constant, yielding a sol'n of

X(t)= Ae^{0}+ Be^{-t}+ C

But how does one solve a 2nd order equation that also has another t variable in it, such as:

\frac {\partial^2X(t)}{\partial t^2} + \frac{1}{t} \frac{\partial X(t)}{\partial t} = C?

 

[Matthew Rodman]

First of all, you only seem to have one independent variable, so it may suitable to express your equation as

\frac{d^2 X(t)}{dt^2} + \frac{1}{t} \frac{d X(t)}{dt} = C

(note total derivative, not partial). Also, since no X(t) appears outside a derivative, you effectively have a first order equation, namely

\frac{dp}{dt} + \frac{p}{t} = C

where

p(t) = \frac{dX(t)}{dt}

Now, any first order equation of the form

\frac{dy}{dx} + s(x) y + r(x) = 0

has the solution

y(x) = -e^{-\int s(x) dx} \int r(x) e^{\int s(x) dx} dx

(just differentiate this and you'll see it works) Hence you can solve for p(t), and then for X(t).

 

[Peregrine]

Ah, that's a very nice way of framing the equation, I hadn't thought of that. Thanks!