Solving a C Local Variable Issue

[Nothing000]

Will someone please help me. I can not fiugure out how to get a local variables value to go from one function to another. Here is the source code:

#include <stdio.h>

int f1(int b);


int main()
{
int a = 0;
int b = 0;

f1();
printf("The value returned TO main() FROM f1() is:\n", a);



return 0;
}

int f1()
{
int a = 0;

printf("Enter a whole number.\n");
scanf("%d", a);

return a;
}

 

[Nothing000]

How do I return the value a back to the main function.

 

[DaveC426913]

What problem are you having? Does the above not work?

 

[Nothing000]

The second function asks for input by the user and stores that as the variable a. But how do I get the value of a back to the main function.

 

[Nothing000]

The big question I have is this: How would I get the variable a to go to the function f2 in this
#include <stdio.h>

int f1(int );
int f2(int );

int main()
{
int a = 0;
int b = 0;

f1();
printf("The value returned TO main() FROM f1() is:\n", a);
f2();
return 0;
}int f1()
{
int a = 0;

printf("Enter a whole number.\n");
scanf("%d", a);

return a;
}


int f2()
{
printf("The value you entered for a is:%d\n", a);
}

 

[Nothing000]

Can anyone help me?

 

[nmtim]

Declare your function as returning int, float, etc. Then assign it to a variable of that type. For f2, declare it as taking a parameter of appropriate type, and then pass the argument to it. In C++

#include <iostream>

int f1();
void f2( int arg);

int main()
{
    int a = f1();
    f2(a);
    return 0;
}

int f1()
{
    return 42;
}

void f2( int arg)
{
    std::cout << "f1 returned " << a << std::endl;
    return;
}

Good luck,
Tim

 

[DaveC426913]

Oh, I see the problem, when you call the function f1, you need to put the returned value somewhere when it comes back.

int x = f1();
printf("The value returned TO main() FROM f1() is:\n", x);

I see nmtim has already addressed that.