MHB Solving a High School Algebra Proof Using Constractive Dilemma

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The discussion focuses on applying the constractive dilemma in high school algebra proofs, specifically using the propositional law that states if P or Q is true, along with P implying S and Q implying T, then S or T must also be true. Participants are encouraged to provide examples of algebra proofs that utilize this law effectively. An example is provided to illustrate the application of the constractive dilemma in a proof context. The conversation emphasizes the importance of understanding this logical structure in solving algebraic problems. Overall, the thread aims to enhance comprehension of logical reasoning in algebra.
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Right any high school algebra proof where the constractive dilemma propositional law is usedConstractive dilemma being the following propositional law:

From PvQ and P=>S and Q=>T we can infer SvT
 
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solakis said:
Right any high school algebra proof where the constractive dilemma propositional law is usedConstractive dilemma being the following propositional law:

From PvQ and P=>S and Q=>T we can infer SvT
An example:

Prove:$$\forall x(x^2\geq 0)$$

Proof:
$$x\geq 0\vee x<o$$

1) for $$x\geq 0\implies x.x\geq 0.x\implies x^2\geq 0$$

2) for $$x<0\implies (-x)>0\implies (-x)(-x)>0\implies x^2\geq 0$$

Now if we put P=$$x\geq 0, $$Q=$$x<0$$

AND S=T=$$x^2\geq 0$$

We have the application of the constractive dilemma propositional law in the above proof
 
Here is a little puzzle from the book 100 Geometric Games by Pierre Berloquin. The side of a small square is one meter long and the side of a larger square one and a half meters long. One vertex of the large square is at the center of the small square. The side of the large square cuts two sides of the small square into one- third parts and two-thirds parts. What is the area where the squares overlap?

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