MHB Solving Acute Triangle Angles Given $A,B,C$ & Equations

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SUMMARY

The discussion focuses on solving for the cosine of the sum of angles \(A\) and \(C\) in an acute triangle given the equations \((5+4\cos A)(5-4\cos B)=9\) and \((13-12\cos B)(13-12\cos C)=25\). The relationship \(A+B+C=180^{\circ}\) and the identity \(\cos B=-\cos(A+C)\) are crucial for deriving the solution. Participants suggest isolating \(\cos B\) in both equations as a viable next step to progress in solving the problem.

PREREQUISITES
  • Understanding of acute triangle properties
  • Knowledge of trigonometric identities
  • Familiarity with algebraic manipulation of equations
  • Experience with cosine functions and their relationships
NEXT STEPS
  • Isolate \(\cos B\) in the equations provided
  • Explore trigonometric identities related to angle sums
  • Investigate properties of acute triangles and their angles
  • Practice solving similar trigonometric equations
USEFUL FOR

Mathematicians, students studying trigonometry, and anyone interested in solving geometric problems involving acute triangles and trigonometric identities.

maxkor
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Given that $A,B,C$ be angles in an acute triangle.

If $(5+4\cos A)(5-4\cos B)=9$ and $(13-12\cos B)(13-12\cos C)=25$

find $cos(A+C)$.
I know $A+B+C=180^{o}$ and $\cos B=-\cos(A+C)$ and what next?
 
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Hi, maxkor!(Wave)

Thankyou for sharing your problem on the MHB site!

You ask for the next step. One way (which worked for me) would be to isolate $\cos B$ in both equations.

I suggest, you try this out(Nod)
 

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