Solving Augmented Matrices with Gaussian Method

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Homework Help Overview

The discussion revolves around solving a system of equations represented by an augmented matrix using the Gaussian elimination method. The original poster presents an augmented matrix and seeks clarification on the steps taken to transform it into a reduced form as shown in their textbook.

Discussion Character

  • Exploratory, Conceptual clarification

Approaches and Questions Raised

  • The original poster attempts to understand the transformation process of the augmented matrix using Gaussian elimination, expressing confusion over the steps involved. Some participants question the clarity of external resources provided, while others suggest specific operations that could be applied to achieve the desired form.

Discussion Status

The discussion is ongoing, with participants exploring different aspects of the Gaussian elimination process. Some guidance has been offered regarding the operations to perform on the rows, but there is no explicit consensus on the best approach or clarity on the original poster's confusion.

Contextual Notes

The original poster indicates that the textbook does not provide detailed steps for the Gaussian method, which contributes to their uncertainty. There is a mention of an external link that was found unhelpful, highlighting a potential gap in available resources.

kash-k
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|1 -5 2 |-5
|3 -14 3 |-8
|4 -18 8 |-8

above is a augmented matrix of a 3 equations. now i know that you can solve these via simul. equations however, my textbook solves them via some gaussian method but doesn't mention how it's done. it just shows -

1 -5 2 |-5
0 1 -3 |7
0 0 1 |-2

how does the textbook go from augment 1 to augment 2 using this guassian method?

thanks in advance :)
 
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did you read it?
because i read it before i posted and let me tell you it's not helpful.
 
Why isn't it helpful? Did you try following the example? It seems ok to me. So it goes like this:
You multiply the first row by a constant such that when it is added to the 2nd row, the left most number of the second row becomes 0. Do that to the 3rd row, then use the second row as a reference to reduce the 3rd row.
 

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