Solving Collision & Rotation Q: Find Impulse, Force, Speed, Length

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SUMMARY

The discussion focuses on solving a physics problem involving collision and rotation, specifically analyzing the elastic collision between a 0.5 kg steel ball and a 2 kg steel block. The force during the collision is defined by the equation F(t) = 8×10^6t – 2×10^9t^2 for 0 ≤ t ≤ 4 ms. Key calculations include determining the impulse on the block, the average force during contact, the maximum force, and the block's speed post-collision. The solution requires integrating the force equation to find the impulse and average force.

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Homework Statement


hi guys,, got a question about collision + rotation ,, the following question is :
A steel ball of mass 0.5 kg is attached to a cord that is fixed at the other end. The ball
is then released when the cord is horizontal, as shown in the figure. At the bottom of its
path, the ball elastically strikes a 2 kg steel block initially at rest on a frictionless
horizontal surface. The ball is in contact with the block for 2 ms, and the force due to the
elastic collision is given by:
F(t) = 8×106t – 2×109t^2
for 0 ≤ t ≤ 4 ms, where t is the time in seconds. Both the ball and block are considered as
point particles.

Find:
a) the impulse on the block due to the collision.
b) the average force of the block from the ball during the period of contact.
c) the maximum force on the block during the period of contact.
d) the speed of block immediately after the collision and the length of the cord.

Homework Equations





The Attempt at a Solution


i know that J=Favg delta(T) but i don't know either of them and i don't know how to answer the first question ,, i need a way to answer it please so i can continue solving the others
 

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I'f I'm not wrong You should integrate the force equation, aka calculate the area under the Graph in bounds 2,0 also convert to seconds.
 

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