Solving D.eq. with Homogeneous Method: Tips and Tricks for Beginners

  • Context: Undergrad 
  • Thread starter Thread starter em919
  • Start date Start date
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
4 replies · 3K views
em919
Messages
2
Reaction score
0
I need some help to solve this D.eq. I've tried the homogeneous method but I didn't work!

Which method can I use?

y'=(-3x+4y-18)/(2x-y+7)
 
Physics news on Phys.org
Hi, em919! ;)

First of all, you need to solve the simultaneous equations

[tex]-3x+4y-18 = 0,[/tex]

[tex]2x-y+7 = 0.[/tex]​

If the solution to this set of simultaneous equations is [tex](x_1, y_1)[/tex], you need to make a couple of changes of variables: [tex]t = x + x_1[/tex] and [tex]z = y + y_1[/tex]. Your new independent variable will be [tex]t[/tex] and your new dependent variable will be [tex]z[/tex]; you'll see that this new differential equation in [tex]z[/tex] is homogeneous. Once you solve this equation, you need to plug back into get the solution in terms of [tex]y[/tex] and [tex]x[/tex].

Hope this helps. :)
 
When I do this the constants go away but what should I do with the other side of the d.eq?
 
Differentiate both sides in [tex]z = y + y_1[/tex]; you'll see that [tex]z' = y'[/tex].