Solving Diffraction Grating Homework: Max Wavelength at 11°

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Homework Help Overview

The discussion revolves around a diffraction grating problem involving the calculation of visible wavelengths that produce a maximum at a specific angle of 11°. The subject area is optics, specifically diffraction and wave behavior in relation to grating equations.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the equation d*sinθ = m*λ and the significance of the variable m, with some questioning its value in this context. There is mention of using whole numbers for m and the possibility of multiple solutions.

Discussion Status

The discussion is ongoing, with participants sharing their interpretations and attempts to solve the problem. Some guidance has been offered regarding the use of whole numbers for m, and there is an acknowledgment of the potential for multiple valid wavelengths.

Contextual Notes

There is a note that the original poster is uncertain about the value of m and its implications for the solution. The conversation reflects a collaborative effort to clarify assumptions and explore the problem further.

Swan
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Homework Statement


A monochromatic plane wave is normally incident on a diffraction grating with 105 lines/m. For what visible wavelengths would this grating produce a maximum at 11°.

Homework Equations


d*sinθ = m*λ


The Attempt at a Solution


d = 1 x 10-5 m

I don't get how to actually solve it because i don't know what the m for this situation would be.
 
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Hi Swan! :smile:
Swan said:
For what visible wavelengths would this grating produce a maximum at 11°.
…
I don't get how to actually solve it because i don't know what the m for this situation would be.

(we usually use "n", not "m")

it can be any whole number …

there may be more than one value for which there is a solution :wink:
 
tiny-tim said:
Hi Swan! :smile:


(we usually use "n", not "m")

it can be any whole number …

there may be more than one value for which there is a solution :wink:

Hello tiny-tim. Thank You for replying. How would i go about solving this question?
 
by using your equation …

what do you get? :smile:​
 
tiny-tim said:
by using your equation …

what do you get? :smile:​

I got at m = 3 and m = 4 the diffraction grating would produce a maximum at 11° at visible wavelengths of 636 nm, 477 nm respectively to m = 3, m = 4.
 

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