Solving Electrical Currents Equations

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neb1627
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Circuit schematic of two car batteries connected with jumper cables: a live battery of 13 V with a 0.023 Ω resistor, a dead battery of 9 V with a 2.7 Ω resistor, and a 0.038 Ω starter resistor on the bottom loop.



9 - 2.7(I) - .038(I) = 0
13 - .023(I) + 2.7(I) - 9 = 0

I don't know how the dead battery effects it and how to figure out the
different currents thru the different resistors
 
Kirchoff Loop rules. Remeber that when you jump start a car, you are "restarting" the battery as well.