Solving Equations: 3x + (-3) = x + 199, -300 -(-4x) = + -8x

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The discussion focuses on solving two algebraic equations: 3x + (-3) = x + 199 and -300 - (-4x) = ± -8x. The first equation simplifies to x = 101, while the second equation can be approached by isolating x through two methods: squaring both sides to form a quadratic equation or considering separate cases for ±8x. Participants emphasize the importance of correctly simplifying terms, such as recognizing that -(-4x) equals 4x.

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I have just been doing some algebra homework. The are just problems that I can't work out. I wonder if anyone can explain how to solve them?

3x + (-3) = x + 199
x = ?
I know the answer is x = 101 but I haven't worked it out in the right way. I just did it by deduction which took ages. What is the right way to tackle this problem?

I have the same problem with this one. I know that x = 25 but how do you work it out?

-300 -(-4x) = + -8x
 
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[tex]3x-3=x+199[/tex]

You're trying to solve for x so the ultimate goal here is to move all the x onto one side of the equation, and then simplify to isolate it, x=...

[tex]-300-(-4x)=\pm 8x[/tex]

Is that actually meant to be a [itex]\pm[/itex]? Because if so, the difficulty between the first and second equation is pretty significant. Unless of course I misread the first equation?

Anyway, you can do this by mainly two ways:
1) square both sides and solve the quadratic
2) Take separate cases, first use 8x and then -8x

Oh and you do realize that [itex]-(-4x)=4x[/itex], right?
 

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