- #1

anto

- 1

- 0

- Homework Statement
- 1)for an object of size 0.5 Angstrom, what is the longest-wavelength photon with which it can be observed?

2)for the object of problem 1, what is the smallest-energy electron which can be used to make the measurement?

- Relevant Equations
- ∆E∆t = h/4(phi)

∆p∆x = h/4(phi)

∆λ = (∆E/E)λ

for the first question, i thougth that 0,5 A is the answer?

for the second question:

i used the E =hc/λ to found the E. but i got a little confused which equations to find ∆E, since there's no ∆t. or should i search the momentum, then use the λ= h/p ?

for the second question:

i used the E =hc/λ to found the E. but i got a little confused which equations to find ∆E, since there's no ∆t. or should i search the momentum, then use the λ= h/p ?

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