Solving for inertia and angular speed

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A 60kg skater starts spinning at an angular speed of 6.0 rad/s and reduces her moment of inertia by 50% by changing her arm position. The relationship between initial and final angular speed is expressed through the equation I(initial)ω(initial) = I(final)ω(final). The initial moment of inertia is represented as I, and the final moment of inertia becomes 0.5I. By substituting these values into the equation, the final angular speed is calculated to be 12 rad/s. The discussion clarifies that while mass and moment of inertia are not interchangeable, the ratio of their changes is what determines the final angular speed.
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A 60kg skater begins a spin with an angular speed of 6.0 rad/s. By changing the position of her arms, the skater decreases her moment of inertia by 50%. What is the skater's final angular speed?

I(initial)ω(initial) = I(final)ω(final)

I used 60 kg as my inertia, is inertia and mass interchangeable in this example? Then I used 30kg because her inertia is 1/2 in the final inertia

60 (6.0) = 30ω

360 = 30ω

ω = 12 rad/sec

I said above but my biggest problem with this equation is it seems to simple, I did not think mass and inertia were able to be interchangeable, but there is no radius or time given so I am not sure what else I could solve for. If my answer is correct, why is inertia and mass equal in this example?
 
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physicsballer2 said:
If my answer is correct, why is inertia and mass equal in this example?
Mass and moment of inertia are not equal. You won't need any values for the moment of inertia; All that matters in the ratio of before and after she moves her arms.

Just call the initial moment of inertia I. What does that make the final moment of inertia?
 
The final moment of inertia is 1/2 the initial, so .5I
 
physicsballer2 said:
The final moment of inertia is 1/2 the initial, so .5I
Exactly. So just plug those values into the formula and solve for ωfinal. (The "I" will cancel.)
 
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