Albert1 Messages 1,221 Reaction score 0 Thread starter Nov 15, 2016 #1 $p,q,r$ are all primes ,and $3p^4-5q^4-4r^2=26$ find $(p,q,r)=?$
Albert1 Messages 1,221 Reaction score 0 Nov 21, 2016 #2 Albert said: $p,q,r$ are all primes ,and $3p^4-5q^4-4r^2=26---(1)$ find $(p,q,r)=?$ hint: Spoiler (1) mod 3 we have : $q^4-r^2\equiv -1 \,\,(mod \,\, 3)$
Albert said: $p,q,r$ are all primes ,and $3p^4-5q^4-4r^2=26---(1)$ find $(p,q,r)=?$ hint: Spoiler (1) mod 3 we have : $q^4-r^2\equiv -1 \,\,(mod \,\, 3)$