- #1

Justforthisquestion1

- 30

- 2

- Homework Statement
- I am looking for the distance x from the center of mass of a rod with I(cm) = 1/12 * m * l^2 were i can apply a Force F over a time delta t so that the rod does excactly one revolution before he is back at its original height.

- Relevant Equations
- Torque, Rotational Energy, Kinetic Energy, angular momentum

Honestly i have very little idea.

F * delta t = p

F * delta t /m = v

So i know the speed of the rod

And i know that however high the rod is supposed to go, when its back down it should have done excactly one revolution.

I have the feeling that I should

So probably i have to use something like

1/2 *a * T^2 = h

and

omega * T = pi?

F * delta t = p

F * delta t /m = v

So i know the speed of the rod

And i know that however high the rod is supposed to go, when its back down it should have done excactly one revolution.

I have the feeling that I should

So probably i have to use something like

1/2 *a * T^2 = h

and

omega * T = pi?