Solving for the Inverse of a Rational Function

  • Context: High School 
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Discussion Overview

The discussion revolves around finding the inverse of the rational function f(x) = 1/(x+1) - 2/9. Participants explore the process of determining f-1(y) and share their approaches and challenges in manipulating the function.

Discussion Character

  • Exploratory, Technical explanation, Homework-related

Main Points Raised

  • One participant expresses a desire to find the inverse of the function and begins the process.
  • Another participant asks for details on what has been attempted so far, indicating a collaborative approach.
  • A third participant provides a transformation suggestion, rewriting the function in terms of y and advising caution with algebraic steps.
  • This same participant notes a formatting issue with the mathematical expressions in the forum, questioning if it is a universal problem.
  • A later reply indicates that the original poster successfully found the inverse after the guidance provided.

Areas of Agreement / Disagreement

There is no explicit consensus on the method used to find the inverse, but participants engage in a collaborative exploration of the problem. The discussion remains focused on the process rather than reaching a definitive conclusion.

Contextual Notes

Some participants mention difficulties with text formatting, which may affect the clarity of mathematical expressions presented in the discussion.

Who May Find This Useful

Students or individuals interested in understanding the process of finding inverses of rational functions, particularly in a collaborative forum setting.

Mathysics
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f(x) = 1/(x+1) - 2/9

just wondering what's f-1 (y) will be

ill have a go at it now thx
 
Last edited:
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Well, what have you tried so far?
 


You have some text-form expression difficulties. You seem to want to find the inverse of
f(x) = [tex]\frac{1}{x+1}[/tex] - [tex]\frac{2}{9}[/tex]
In which you may create the transformation using f(x)=y of
x = [tex]\frac{1}{y+1}[/tex] - [tex]\frac{2}{9}[/tex]

Solve for y which will really be your inverse of the original function. Watch your algebra steps carefully, and then try checking your result again.

That looks very bad when I view the forum result; the 'tex' tagged portions look blackened and are not readable or legible. Is this just me here, or does it look that way for everybody?
 
Last edited:


wow thank you very much i got it now :)
 
Last edited:

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