- #1

KevinL

- 37

- 0

y'' + 2y' = 3t+2

The only method we have been taught is to first find the general solution of the unforced equation and then find the particular solution.

For general solution, the characteristic polynomial is L^2 + 2L = 0 (where L= lambda)

L^2 = -2L

L = -2

So general solution of unforced equation is y(t) = k1e^-2t +K2te^-2t

I am fairly certain about the above. The particular solution is a bit trickier for me.

guess: yp(t) = At + b

Plug in: 2A = 3t + 2

A = (3/2)t + 1

Is that correct? It seems like an odd answer, and B sort of just disappeared.