Solving Higher Degree Polynomial For Real Solution(s).

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SUMMARY

The discussion focuses on finding real solutions to the polynomial equation $$(x^2-9x-1)^{10}+99x^{10}=10x^9(x^2-1)$$. Participants confirm that there are two real solutions, while initially speculating about the existence of additional solutions. The conversation highlights the importance of graphing the function to visualize the roots, although some members note that graphing may not be the most effective method for this particular problem. Overall, the consensus is that only two real solutions exist for the given polynomial equation.

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anemone
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Find real solution(s) to the equation $$(x^2-9x-1)^{10}+99x^{10}=10x^9(x^2-1)$$
 
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anemone said:
Find real solution(s) to the equation $$(x^2-9x-1)^{10}+99x^{10}=10x^9(x^2-1)$$
Hint 1:
Divide both sides by $x^{10}$.
Hint 2:
Let $y = x-\frac1x$.
Hint 3:
What happens when $y=10$?
That will give you two real solutions. There are two others, but I do not think that they can be explicitly determined.
 
Hi Opalg,

I thank you for taking the time to share your helpful hints in this challenge problem.

My approach is different from yours and I wish to share it here too.

Hint 1:
We first rewrite the equation as $$(x^2-9x-1)^{10}-10x^9(x^2-9x-1)+9x^{10}=0$$

Hint 2:
Assume that $$(x^2-9x-1)^{10}+9x^{10}=10x^9(x^2-9x-1)$$ is true.

Hint 3:
We need to show that $$(x^2-9x-1)^{10}=x^{10}$$ and $$x^9(x^2-9x-1)=x^{10}$$ are true by obtaining two equivalent equation, i.e. $$x^2-10x-1=0$$ in order to prove our assumption is true.

Hint 4:
The original problem is solved if we solve for x for $$x^2-10x-1=0$$

Opalg said:
That will give you two real solutions. There are two others, but I do not think that they can be explicitly determined.

I failed to realize that there are two other real solutions to this problem. Would you mind to teach me how to tell how many real solutions there are for this particular problem?

Thanks in advance.
 
anemone said:
I failed to realize that there are two other real solutions to this problem. Would you mind to teach me how to tell how many real solutions there are for this particular problem?
That was my silly mistake. There are no other real solutions. Sorry about that.
 
Opalg said:
That was my silly mistake. There are no other real solutions. Sorry about that.

I see...hey, don't worry about that! :)

You are and always will be one of my favorite mathematicians at this site!:o:p:)
 
anemone said:
Find real solution(s) to the equation $$(x^2-9x-1)^{10}+99x^{10}=10x^9(x^2-1)$$
Graph it! Hey, I'm a Physicist. (Beer) (Physics is always better with beer.)

-Dan
 
topsquark said:
Graph it! Hey, I'm a Physicist. (Beer) (Physics is always better with beer.)

-Dan

Indeed. I am now confident the real roots are between $-\infty$ and $+\infty$, more or less (Smoking)
 
topsquark said:
Graph it! Hey, I'm a Physicist. (Beer) (Physics is always better with beer.)

-Dan

Unfortunately in this case graphing in not a comfortable way to arrive to the solution (Wasntme)...

http://www.123homepage.it/u/i69151835._szw380h285_.jpg.jfif

All is allways better with beer! (Beer)...Kind regards $\chi$ $\sigma$
 

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