Solving Jet Plane Velocity and Acceleration using Physics Formulas

  • Thread starter Thread starter jmd0221
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on calculating the x component of a jet plane's average acceleration using the velocity components Vx and time intervals. Given Vx values of 625 at time 3.85 seconds and 838 at time 6.52 seconds, the average acceleration can be determined using the formula: average acceleration = (Vx_final - Vx_initial) / (t_final - t_initial). The calculated average acceleration for the x component is approximately 55.5 m/s².

PREREQUISITES
  • Understanding of basic physics concepts, specifically kinematics.
  • Familiarity with velocity and acceleration definitions.
  • Knowledge of time intervals in motion analysis.
  • Ability to apply mathematical formulas to solve physics problems.
NEXT STEPS
  • Study the kinematic equations for motion in two dimensions.
  • Learn about vector components and their significance in physics.
  • Explore the concept of instantaneous vs. average acceleration.
  • Review examples of calculating acceleration in real-world scenarios.
USEFUL FOR

Students studying physics, educators teaching kinematics, and anyone interested in understanding motion dynamics in aviation.

jmd0221
Messages
1
Reaction score
0
Hi, I am stuck on this problem and its probably easier than I think, can anyone help?

At an air show, a jet plane has velocity components Vx= 625 and Vy= 415 at time 3.85 and Vx= 838 and Vy= 365 at time 6.52 .
For this time interval, find the x component of the plane's average acceleration?

What formula would I use?? Thank so much been on this question of 1hr now.. :)
 
Physics news on Phys.org
The x component of the acceleration is the amount by which the x component of the velocity has changed in this interval.
 

Similar threads

  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
Replies
13
Views
11K
Replies
3
Views
4K
Replies
10
Views
4K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
25
Views
2K
  • · Replies 8 ·
Replies
8
Views
3K
  • · Replies 7 ·
Replies
7
Views
1K