Solving log base 2 of x(x+3)^2/(4x+2) = 1

[DeanBH]

i've got a logashizm problem to this point

the log is base 2log (x(x+3)^2 / (4x+2)) = 1

apparently x(x+3)^2 / (4x+2) = 2

no idea why, halp?

thxgod damn it, nvm

2^1 = (x(x+3)^2 / (4x+2)) when you take the damn log out.

 

[BrendanH]

exactly