Solving Long Jump: Find Take-Off Speed

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SUMMARY

The problem involves calculating the take-off speed of an athlete executing a long jump at a 29.6° angle, covering a horizontal distance of 7.43 meters. The key variables include time (t), initial velocity in the x direction (Vix), initial velocity in the y direction (Viy), and the overall initial speed (Vi). To solve this, kinematic equations for projectile motion must be applied, specifically focusing on horizontal displacement and vertical motion equations.

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  • Understanding of projectile motion principles
  • Familiarity with kinematic equations
  • Basic trigonometry for angle calculations
  • Ability to solve for multiple variables in physics equations
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  • Review kinematic equations for projectile motion
  • Learn how to decompose initial velocity into horizontal and vertical components
  • Study the effects of launch angle on projectile distance
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This discussion is beneficial for physics students, educators, and anyone interested in understanding the mechanics of projectile motion, particularly in sports contexts like long jump analysis.

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Homework Statement


An athlete executing a long jump leaves the ground at a 29.6° angle and travels 7.43 m. What was the take-off speed?

I have 4 unknown variables: t, initial velocity in the x direction (Vix), initial velocity in the y direction (Viy). and the initial speed which I'm trying to find (Vi).

Which kinematic equations do I use? I've been stuck on this problem for a day now.
 
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It depends on what they mean by 'travels 7.43m'... They probably mean his horizontal displacement is 7.43m when he hits the ground. I'm going to assume this is the case.

Have you done similar questions before? what kind of motion can we assume this guy has while he is in the air?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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