Solving Rate of Reaction Problems: Ethyl Ethanoate and Sodium Hydroxide

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Discussion Overview

The discussion centers around a homework problem involving the rate of reaction between ethyl ethanoate and sodium hydroxide, specifically focusing on the order of reaction with respect to hydroxide ions and total order. Participants explore the implications of half-life and equimolar concentrations in determining reaction order.

Discussion Character

  • Homework-related
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant notes that the half-life of the reaction doubles, suggesting a second-order reaction.
  • Another participant questions whether the order identified pertains to hydroxide ions or the total order of the reaction, expressing confusion over the mark scheme's indication that it is the total order.
  • A different participant mentions that various sources indicate the graph should reflect order only with respect to hydroxide ions, raising a point of contention regarding the interpretation of the data.
  • One participant requests additional information to clarify the context of the problem, indicating a lack of access to the original material referenced.

Areas of Agreement / Disagreement

Participants express differing views on whether the order of reaction should be considered with respect to hydroxide ions alone or as a total order. The discussion remains unresolved, with no consensus reached on the correct interpretation.

Contextual Notes

Participants highlight the relevance of equimolar concentrations of ester and NaOH at the start of the reaction, though the implications of this detail are not fully explored or agreed upon.

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Homework Statement


http://www.mrev.org.uk/A-Level_Site/New%20A-Level%20Unit%204/Rates.html
(the answers are at the top - see link)

Could someone please help me with the question (about half way through) on ethyl ethanoate and sodium hydroxide.
in cii) we identified the half life doubles
ciii) we identified the order is second order

for part civ) we are asked is this the order for OH- ions or total order.
I would have said OH- order BUT the answer is total order.
Please could someone explain this (the mark schemes explanation is ester and NaOH are equimolar at the start - how is this relevant)

thanks


Homework Equations


NONE


The Attempt at a Solution


I have shown my attempts above in the body of this question
 
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questions like this come up often and I am worried it may come up in mine so i would really like to understand the theory behind it
 
i read a few books and they all agree the graph should only show order with respect to OH ions
why is this not the case here
 
It might be better if you present the relevant information here. I couldn't find what you're talking about!
 

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