Solving Schrodinger's Eqn for Quantum Ring: Boundary Conditions?

[Haxx0rm4ster]

When solving Schrödinger's eqn for a quantum ring, what would be the boundary conditions?

The solution (polar) should be
Ψ(Φ) = A exp(ikΦ) + B exp(-ikΦ)

And I believe the boundary conditions are
Ψ(0) = Ψ(2pi)
Ψ(0) = A + B
Ψ(2pi) = A exp(ik*2π) + B exp(ik*2π)


and I suppose I can safely say that
Ψ(0) = 0

From these conditions/assumptions,
k = n, n = 1,2,3...
B = -A,

And therefore
Ψ(Φ) = A exp(inΦ) - A exp(-inΦ)

Which can be expressed as
Ψ(Φ) = 2Ai sin(nΦ)

I'm just wondering, are my boundary condition assumptions complete and correct?

Thanks

 

[nnnm4]

No the phi(0) = 0 boundary condition is not a good one. This eliminates and cosine behavior in the wavefunction. Your second boundary condition is that the wavefunction be continuously differentiable.

 

[Nano-Passion]

Hey, sorry to hijack your thread but what's a quantum ring? I'm curious.

 

[Haxx0rm4ster]

By quantum ring, I'm referring to something like a quantum wire looped around in the shape of a ring.

 

[Avodyne]

The correct boundary condition is periodicity: Ψ(Φ) = Ψ(Φ+2π).

 

[nnnm4]

Which he already used, so the periodicity of the derivative is the other boundary condition.