Solving Sin(theta) = dy/dx | Acoustics Course Prep

[rexregisanimi]

In preparing for an acoustics course, I ran across the following sentence which confused me:

"If (theta) is small, sin(theta) may be replaced by [partial]dy/dx."

I expected to see sin(theta) = (theta) so this threw me off. This came up in the derevation of the one dimensional wave equation after approximating (by Taylor series) the transverse force on a mass element of a tensioned string with [partial]d(Tsin(theta))/dx. The approximation in question thus gave T*([partial]d2y/dx2)*dx.

In the original setup, x and y are cartesian axis in physical 2D space and (theta) is the angle the string (with tension T) makes from the x-axis after displacement from equalibrium.

I've never seen sine approximated by dy/dx before and was hoping somebody might shed some light for me :)

 

[LCKurtz]

When $\theta$ is small, $sin\theta \approx \tan\theta = \frac{dy}{dx}$. In the derivation for the vibrating string, $\theta$ is the slope angle of the string.

 

[rexregisanimi]

Thank you! :)

 

[rcgldr]

sin(θ) = Δy / sqrt(Δy^2 + Δx^2). For small θ, Δy is small compared to Δx, so

sin(θ) ≈ Δy / sqrt(0 + Δx^2) = Δy / Δx