Solving Sound Intensity with 2 Shut-Off Engines

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Homework Help Overview

The problem involves calculating sound intensity from a plane with three engines producing 120 dB, and determining the new intensity when two engines are shut off.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants discuss the application of the decibel formula and question the calculations related to sound intensity when engines are turned off. There is confusion about the interpretation of the decibel scale and how it relates to the intensity of sound from multiple sources.

Discussion Status

Some participants are seeking clarification on the calculations presented, particularly regarding the source of certain values in the equations. Others suggest reviewing the concept of decibels to better understand the problem.

Contextual Notes

There appears to be a misunderstanding regarding the relationship between sound intensity and the number of engines, as well as the implications of decibel levels in this context.

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Homework Statement


A person is a certain distance away from a plane with three equally noisy engines at 120 dB. What is the sound intensity if two of the engines are shut off?


Homework Equations


B (in dB) = log I/Io


The Attempt at a Solution


using this equation:
120 dB = 10 log I/Io
10^12 = 10 log (I/10^-12 W/m2)
I = (10^12)(10^-12)
I = 1 W/m2

So, intensity for three engines is 1 W/m2. If two engines turned off, then I'm pretty sure you don't divide the answer by three to get 0.33 W/m2 per engine because the answer is 116. I can't figure out what I'm doing wrong.
 
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On the second line in your solution, where did 1012 come from?
 
Sorry, this should read:

120 dB = 10 log (I/10^-12 W/m2)
10^12 = I \(10^-12)
I = (10^12)(10^-12)
I = 1 W/m2
 
any ideas?
 
I think you need to better understand the meaning of decibel. This might help: http://hyperphysics.phy-astr.gsu.edu/hbase/sound/db.html"
 
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