Sound intensity, also known as acoustic intensity, is defined as the power carried by sound waves per unit area in a direction perpendicular to that area. The SI unit of intensity, which includes sound intensity, is the watt per square meter (W/m2). One application is the noise measurement of sound intensity in the air at a listener's location as a sound energy quantity.Sound intensity is not the same physical quantity as sound pressure. Human hearing is sensitive to sound pressure which is related to sound intensity. In consumer audio electronics, the level differences are called "intensity" differences, but sound intensity is a specifically defined quantity and cannot be sensed by a simple microphone.
Sound intensity level is a logarithmic expression of sound intensity relative to a reference intensity.
The answer key is the light is directed through one polarising filter then filter is rotated and the light changes intensity.
I don't understand how that proves that the light is plane polarised. I think if the light is unpolarised, the intensity will also change when it passes through...
My question is specifically with calculating the intensity. The book solution is
I=P/(4*pi*r^2)
but would this not give me a weaker electrical amplitude in the final calculation after plugging it in to
I=(1/2)*√(ε0/μ0)*(E02) ?
Pretty much, I was picturing a 1x1x1 meters cube of a dark colored, mostly uniform material (limited porosity, no crevices) with a small chamber in its interior - exactly where the center of mass should be. In it, a body emitting light is activated with the goal to find the intensity necessary...
This is problem 62 in Cutnell & Johnson's Physics (9th edition):
Suppose that the light falling on the polarizer in the figure is partially polarized (average intensity \bar S_P) and partially upolarized (average intensity \bar S_U). The total incident intensity is \bar S_P+ \bar S_U and the...
Consider the infrared led TSAL7600 which has the following properties:
$$ \Phi = 35 mW $$
$$ I_e = 25 mW/sr $$
The half angle is ## 30^\circ ## and:
$$ I_r(\theta) = cos^{4.818}(\theta) $$
is a good approximation for the relative radiant intensity.
However, finding the actual radiant...
The data collected from the experiment is,
The first column is the polarizer angle measured in degrees.
The second column is recorded intensity measured in lux.
The third column is the transmitted intensity measured in lux. This is equal to the recorded lux - ambient lux
The fourth column is...
I was looking at the gamma radiation data from IAEA's website:
(https://www-nds.iaea.org/relnsd/vcharthtml/VChartHTML.html)
and was confused by the absolute intensity listed in the page. I Googled it and it seems to be the probability of emission but why it doesn't add up to 100%?
For example...
TL;DR Summary: How do i find the intensity of this wave?
I know I is proportional to amplitude / frequency squared, but I don't know what equation this comes from. And I don't know how to answer this.
If I have on my PC let's say sound on 50% and I increase it on 100%, how would the sound intensity change? Would it be twice bigger? But I think that function of sound intensity level dependent on sound percets is a linear function, isn't it? How to explain it? Why is it the linear function?
My answer is 0.5 m (same as wavelength) but answer key is 1 m.
I thought the maximum intensity occurs at antinode and distance between adjacent antinodes is half of wavelength so the distance between first and third antinode is one wavelength.
Where is my mistake? Thanks
I have realized EIT with continuous laser. What are the requirements for the intensity, duration and repetition frequency if EIT is realized with pulsed laser?
you can attach any reference:biggrin:thanks a lot!
I am calculating Responsivity of a pn junction photodiode (a.k.a the target) by irradiating radiation from LED sources. For this purpose, i have two LEDs, one UV and another green LED. Note that LEDs are placed close to the target.
UV LED : Manufacturer has given total radiant power to be...
a) ##\rho = \frac{I}{c} = \frac{F}{A}## for a perfect absorber
##F = ma## where ##a = \frac{c}{t}##
##\frac{I}{c} = \frac{mc}{tA}##
##I = \frac{I^2 tA}{mc^2} = \frac{P}{A}##
##P = \frac{I^2 tA^2}{mc^2} = \frac{W}{t}##
##W = \frac{I^2 t^2A^2}{mc^2}##
I am unsure what A is. I think it should be...
Here is the solution, I understand how they got E, but I don’t see how they could get E’ from cosine addition formulas? I don’t need to know how to do it with complex numbers.
I found there is kind of solution in Pointon's book: An Introduction to Statistical Physics for Students. But I don't know how to find intensity by using frequency.
We assume incident waves to be:
y(1)=y(o)sin(wt)
y(2)=3y(o)sin(wt+Φ)
As Intensity~(Amplitude)^2
We get y(2)=3y(1)
This gives us I(2)=9I(1)
We assume I(1)=I(o) & I(2)=9I(o)
Resultant Wave Intensity I=I(1)+I(2) +2√(I(1)*I(2))*cosΦ ---->
I(o) + 9I(o) + 6I(o)cosΦ (We can take cos of this...
I haven't been able to pinpoint a definition of "angular divergence" of a laser so by pure intuition I assumed it would be something like ##\theta=\frac{2R}{D}## and with that I have that the radius of the lase beam is ##R=\frac{D\theta}{2}=90\cdot 5 \cdot 10^{-6} m=450\ \mu m## so...
I'd appreciate if someone could check whether my work is correct. The ##x##-##y## symmetry of the aperture separates the Fresnel integral:\begin{align*}
a_p \propto \int_{-a/2}^{a/2} \mathrm{exp}\left(\frac{ikx^2}{2R} \right) dx \int_{-a/2}^{a/2} \mathrm{exp}\left(\frac{iky^2}{2R} \right) dy...
I tried using the equations above, but I wasn't really able to come up with an intuitive explanation. From my understanding, the electric field vector only varies in the x-y plane while the magnetic field vector only varies in the z-y plane. Also, both vary sinusoidally and both reach extrema...
In a single slit diffraction experiment, when we want to calculate the intensity of light on a screen located very far away from the slit, usually Huygens' principle is adopted as a model to perform the calculations.
It is assumed that the width of the slit consists of an infinite number of...
Hello. I am having some trouble to understand the resolution of this question.
We could easily try to calculate the electric field relative resultant at the screen. The problem i am having is about the amplitude of the electric field:
Generally, we have that the intensity part dependent of the...
I was supposed to find the relation among the coefficients $T$ and $R$ which represent the amplitude of the reflected electric field and the transmitted electric field respectively, that is, $$E_{R} = E_{i} R, E_{T} = E_{i} T$$ as well as the coefficients $t$ and $r$, that represent the...
Let a spherical wave propagate from the origin, $y = ADcos(wt-2\pi r/ \lambda)/r$. Also, let a plane wave propagate parallel to the x axis, $y = Acos(wt-2\pi r/ \lambda)$. At x = D there is a flat screen perpendicular to the x axis. Find the interference at the point y on the screen as function...
My Try:
The resultant field is given by
$$\begin{aligned}\overrightarrow{E}=\overrightarrow{E}_{1}+\overrightarrow{E}_{2}=\widehat{i} E_{0}\cos \omega t+\widehat{j}E_{0}\cos \left( \omega t+\phi \right) \\
\Rightarrow E^{2}=E_{0}^{2}\cos ^{2}\omega t+E_{0}^{2}\cos ^{2}\left( \omega t+\phi...
Hi,
If I build a machine that its sole purpose is to radiate xx Hz of electromagnetic wave, how do I calculate the intensity of the waves? Let's say I put it in the room of 30 sq meters.
Thank you.
When the crystal above is illuminated with light of intensity ##I_0##, what is the intensity at the central maximum? (The picture shown above is a 4 x 4 unit cell of the crystal)
The answer is ##(\frac {5} {16} )^2 I_0##. Why?
Apparently, Electric field is proportional to the transparent area...
This the photo of my textbook, Here In the derivation of Electric Field Intensity due to an infinitely long straight uniformly charged wire -
In the figure 1(c).20 Vector E1 and vector E2 are electric fields at point P due to the two line elements as shown in the figure 1(c).20.
But, in this...
In Principles of Lasers by Svelto, while deriving the Planck radiation formula, equation 2.2.3 says $$I_{\nu} = \frac {c_0} {4n} \rho_\nu$$
where ##I_\nu## is the spectral intensity at some hole in the cavity wall (energy per time per area per frequency),
##c_0## is the speed of light in...
I actually am not sure what equations are relevant here but I thought these are the relevant ones.
My Approach:
By Stefan-Boltzman Law, the intensity absorbed by the Earth is given as ## I = e \sigma T^4## where e is the emissivity of Earth, ##\sigma## is Stefan-Boltzman constant and T is the...
I = 1/2 ρvR²w²
I = 1/2 *1.2kg/m³*340m/s*(10 x 10^-6m)²*(2π*440/s)²
I = 0.16 W/m²
This is my answer which does not match the given answer. Am I doing wrong?
\begin{equation}
\chi = n \sigma
\end{equation}
Where Chi is the Opacity, n is the number density of absorbers (constant), and $\sigma$ is the cross section(given).
We define the optical depth is just the number of photon mean-free paths in a given physical step, i.e. if we consider a...
Hello guys, if I have an image with 11x11 pixels and in the center of the image is a square of 5x5 pixels, with the gray level of the background 0 and the gray level of the square is 50. How can I compute the result of the magnitude of edges(intensity of the contour) or better said the gradient...
My attempt:
p and T allows us to calculate ##Z=402 \frac{kg}{sm^2}## using ## Z=p*\sqrt(\frac{\gamma*M}{R*T})## . The sound intensity level at 10 meters allows us to calculate the intensity at 10 meters to be I=10``````^{-7} W/m^2 using ##50 = 10*log(I/I_0)##. Then, using the formula...
Hello there, I've worked through this problem and I would just like to check whether I've understood it correctly. I found ##\vec H##, ##\vec B## and ##\vec M## using Ampere's Law and the above relations as I would for any thin current carrying wire and these were my answers:
$$\vec H = \frac I...
what I've done so far?
-i've determined the vector between the point (4, 0, 0) and the point P.
(4, 6, 8) - (4, 0, 0)
(0, 6, 8)
-The norm of this vector is the radial distance of the line to point P (the value of “ρ” in the formula)
√(0^2 + 6^2 + 8^2) = 10 -> ρ = 10
-and its unit vector is...
The answer is about 40 Watts, but i am really not getting it:
<Pot> = 0.5((pλ)(ωA)²)v
p density linar
λ wavelength
ω angular frequency
A amplitude
v phase speed
Why is this wrong?
(I already tried too by <Pot> = Z*(ωA)²/2)
Z is impedance
So I thought of calculating the path differences between all the 3 points by taking them in pairs of 2.
S1 and S2
S2 and S3
S3 and S1
I got the path differences as λ/3 , λ and 2λ/3
I can now find their phase differences using the equation
Cosx=2π/λ* (path difference)
Then I can apply the...
For a star..
Apparent Magnitude = -2.5log10 I K
And I = I0/d^2
So in terms of I0...
Apparent Magnitude = -2.5log10 (I0/d^2)
And the Stefan-Boltzmann law says:
Energy Flux = Sigma(T^4)
In my reading it says that Intensity is the energy emitted per unit of area per unit of time. It says the same...
To begin with, I am trying to understand how does ##E^2 (x,t)## transform to ##A_y^2 + A_z^2##. And, noting that the already established equation of ##E^2 = E_y^2 + E_z^2##, I would assume that ##E^2 (x,t)## somehow ends up to being ##A_y^2 + A_z^2##. However, noting that ##E^2 = (A_y...
I was looking up the maximal amount of noise allowed by current laws, that one can produce. I found that in my region one can produce sounds of up to 45 dB in the period from 22 pm to 7 am.
But, it seems evident that the decibels fall off as we distance ourselves from the source. So shouldn't...
Hi,
Would it be correct to say that at Brewster's angle, all the incident light which has its electric field parallel to the plane of incidence gets refracted, and the rest of light whose electric field is perpendicular to the plane of incidence gets reflected? For example, if the light whose...
I'm still on part a.
I think that i may have the wrong equation for intensity.
I'm not sure I'm using the right numbers for the "first minimum".
I started with getting the wavelength
λ=(ax)/D
since the first minimum occurs at m = 0.5 I multiplied the distance to the first minimum by 2 to get...
The equation above (from Wikipedia), assumed that the Gaussain beam has polarization in x-direction, as I know that the polarization means that the oscillation direction of the electric field and so the intenisty... so how we get circular intensity in every direction which means in x and y...