Solving Statics Question: Ty/Tx = 0.18/0.24

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Homework Statement


The Bracket BCD Is hinged at C and attached to a control cable at B. For the loading showm, determine the tension in the cable, the reaction at C.

so after attempting this problem for about an hour and still not getting the right
answer I decided to look up the solution. Only to be more confused can someone
explain why they start the solution off with Ty/Tx = 0.18/0.24 ??
How does setting up this ratio correlate to Ty and Tx?
Statics diagram of a bracket BCD hinged at C with a cable from A to B; vertical dimension a = 0.18 m, horizontal 0.24 m, with two 240 N downward loads on the horizontal arm at 0.4 m spacing. Solution shows Ty/Tx = 0.18 m / 0.24 m, Ty = 3/4 Tx, and T = 2.00 kN.
 
David Donald said:

Homework Statement


The Bracket BCD Is hinged at C and attached to a control cable at B. For the loading showm, determine the tension in the cable, the reaction at C.

so after attempting this problem for about an hour and still not getting the right
answer I decided to look up the solution. Only to be more confused can someone
explain why they start the solution off with Ty/Tx = 0.18/0.24 ??
How does setting up this ratio correlate to Ty and Tx?
Solution sketch of a statics problem: a bracket with a cable from A to B, a 0.18 m height and 0.24 m base, with the components Tx and Ty, and equations Ty/Tx = 0.18 m / 0.24 m, Ty = (3/4)Tx and sum of moments about C equal to zero, giving Tx = 1600 N, Ty = 1200 N and T = 2000 N.
Ty/Tx = 0.18/0.24 is the relationship between the two components of the tension in the line AB. By using this relationship, all of the forces acting on the crank mechanism are now acting parallel either to the x or y-axes.