Solving the Equation (y^2)+(y')^2=1: Ideas and Guidance

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Homework Statement



Find a function of y whose square plus the square of its derivative is 1.
i.e. (y^2)+(y')^2=1 and carry out your ideas.


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The Attempt at a Solution



Can anyone just help me out with this one. Kinda confused by the questioning. Just point me in the right direction.
 
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I still don't see it. How does the derivative factor into it?
 
Dr. Lady is suggesting you simply guess the answer.
Otherwise you have y'=+/-sqrt(1-y^2). You can try to integrate that.