Solving the Salmon Jump Problem: How High Can it Go?

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The Salmon Jump Problem involves calculating the maximum height a salmon can jump when swimming upward at a speed of 5 meters per second. To solve this, the relationship between initial velocity, final velocity, and height is analyzed using projectile motion equations. Assuming the jump angle is 90 degrees, the maximum height is calculated to be 1.275 meters above the water. The discussion emphasizes breaking down the problem and applying relevant physics equations. Understanding these concepts is crucial for solving similar problems effectively.
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hi everyone! ok so i was doing my homework and i came upon this one problem which completely stummped me and so if someone could set me in the right direction i would be very thankful! here is the promblem: If a salmon swims sraight upward in the water fast enough to break through the suface at a speed of 5 meters per second, how high can it jump above water?
 
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So, you're given the initial velocity and asked to find the maximum height. What can you say about the velocity at the top of the jump ? How are initial and final velocities related to distance (height) ?

That's more than I should be giving away at this stage...
 


Hi there! The Salmon Jump Problem is definitely a tricky one, but don't worry, I can help guide you in the right direction. First, let's break down the problem into smaller parts. We know that the salmon is swimming straight upward in the water at a speed of 5 meters per second. This means that it is accelerating at a constant rate of 5 meters per second squared.

Now, to find the maximum height the salmon can jump, we need to use the equation for projectile motion: h = (v^2 sin^2θ)/2g, where h is the maximum height, v is the initial velocity (in this case, 5 meters per second), θ is the angle at which the salmon jumps (we can assume it is 90 degrees or straight up), and g is the acceleration due to gravity (9.8 meters per second squared).

Plugging in the values, we get: h = (5^2 sin^2(90))/2(9.8) = 1.275 meters. So, the salmon can jump a maximum height of 1.275 meters above water.

I hope this helps you with your homework! Remember to always break down the problem into smaller parts and use the appropriate equations. Good luck!
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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