- #1

- 7

- 1

du[x]/dx= - a v[x] +b ∫〖[1-(y-x)^4 〗].(v[y]-v[x])dy

And

(dv[x])/dx= - f u[x] -g ∫〖[1-(y-x)^4 〗].u[y]dy

With the initial conditions:

v[0]=e and u[1]=0

a,b,f,g and e are positive constants

Both integrals are from y=0 to y=1.

The unknowns are u[x] and v[x].