Solving y''+y=δ(t-2π)cos(t) with Laplace transform

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Homework Statement


[tex]y''+y=\delta (t-2\pi )cos(t)[/tex]
[tex]y(0)=0,y'(0)=1[/tex]


Homework Equations





The Attempt at a Solution


The left side is (s^2+1)Y(s)-1=RHS

My problem is the fact that cosine is being multiplied by the delta function. I put it in the form of an intergral but I don't know what to do from there.
 
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Well, good! Delta functions usually make integrals trivial. What integral did you get?
 
hmm, i don't know what is this question, may i know, what topic should i study for this question?
 
Differential Equations -Laplace transforms

OHHHH waitttt does the delta function just determine the bound of my intergral?