Some contradiction I can't explain about e^(ix)

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Ahmes
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Let k be a real number (not necessarily an integer).
[tex]e^{i\cdot2\pi\cdot k}=\cos(2\pi k) + i\sin(2\pi k)=[/tex] some complex number on the unit circe.
BUT
[tex]e^{i\cdot2\pi\cdot k}=(e^{i2\pi})^k=1^k=1[/tex]

so if take [itex]\tilde{k}=2\pi k[/itex] then [itex]1=e^{i\tilde{k}}=[/itex]every other number on the unit circle.

How can this be explained??
Thanks.
 
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solved... I'm an idiot.
[tex]1^k[/tex] with complex numbers are all the unit's [tex]k^{-1}[/tex] roots...