Some reaction between a proton and antiproton

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SUMMARY

The reaction between a proton and an antiproton, represented as p + \bar{p} → π⁺ + π⁻ + π⁰, is indeed possible and is classified as a strong interaction. The conservation laws are satisfied, allowing for the transformation of quark configurations. The π⁰ meson is a superposition of u\bar{u} and d\bar{d} quark pairs, which confirms its role in the strong interaction process. Understanding how to represent this in Feynman diagrams is essential for visualizing the interaction.

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  • Understanding of particle physics, specifically meson interactions.
  • Familiarity with Feynman diagrams and their construction.
  • Knowledge of quark configurations and their implications in particle interactions.
  • Basic grasp of conservation laws in physics.
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  • Study the construction of Feynman diagrams for strong interactions.
  • Research the properties and configurations of π⁰ mesons in particle physics.
  • Explore conservation laws related to particle interactions in detail.
  • Learn about the role of quark-antiquark pairs in meson formation.
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This discussion is beneficial for physics students, particle physicists, and anyone interested in understanding strong interactions and meson dynamics.

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Homework Statement


Is the following reaction possible? If so, what is the type of interaction (EM, weak or strong)?
[tex]p+\bar{p}\rightarrow\pi^+ + \pi^- + \pi^0[/tex]


Homework Equations


Conservation laws and rules of thumb regarding types of interactions.


The Attempt at a Solution


I don't think any conservation laws are broken so the process is possible. The question is how exactly. I don't have any idea how to put [itex]\pi^0[/itex] into Feynman diagrams... since its a superposition of two separate quark configurations. I drew the following:
http://img220.imageshack.us/img220/6554/pixo3.png
If [itex]\pi^0[/itex] was just [itex]u\bar{u}[/itex] then my question would be whether only changing quark configuration means that it is a strong interaction. And if so, how to draw a Feynman diagram showing what really changed.
But [itex]\pi^0[/itex] is neither it nor [itex]d\bar{d}[/itex] - so what should I do?

Thanks!
 
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The [itex]\pi^0[/itex] is a superposition of [itex]u\bar{u}[/itex] and [itex]d\bar{d}[/itex], so [itex]u\bar{u}[/itex] do form a [itex]\pi^0[/itex].
 
Allowed Strong Interaction
 

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