Temperature for 440 Hz sound wave with 0.82 m wavelength

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leehana10
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The speed of sound at 0°C in open air is 331.3 m/sec. At what temperature would the wavelength of a 440 Hz sound wave be 0.82 meters?

Equation to find the speed of sound: Vт = Vo √(T/273)

T = 273 + t(°C)

My calculations:

Vт = 440 Hz (0.82 m) = 360.8 m/s

Vт = Vo √(T/273)
360.8 m/s = 331.3 m/s (t^2)
-331.3 m/s = -331.3 m/s (t^2)
29.5 = t^2
√(29.5) = t
5.431 = t
 
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360.8 m/s = 331.3 m/s (t^2)
-331.3 m/s = -331.3 m/s (t^2)

How did you get that?
 
Nvm. I got help from a friend. Thank you for your help though!