Speed of Sound in Air Problem- Is this correct?

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Homework Help Overview

The discussion revolves around calculating the speed of sound in air and determining the temperature at which a specific wavelength of a sound wave occurs. The original poster presents a formula and calculations related to the speed of sound and its dependence on temperature.

Discussion Character

  • Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to use a formula relating the speed of sound to temperature and presents calculations to find the temperature corresponding to a wavelength of a sound wave. Some participants question the calculations and seek clarification on the steps taken.

Discussion Status

The discussion includes attempts to clarify the calculations presented by the original poster. While one participant expresses gratitude for help received, there is no explicit consensus on the correctness of the calculations or the approach taken.

Contextual Notes

There appears to be some confusion regarding the calculations and the application of the formula for the speed of sound, as indicated by the questioning of specific steps. The original poster also mentions receiving help from a friend, suggesting potential external assistance in resolving the problem.

leehana10
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The speed of sound at 0°C in open air is 331.3 m/sec. At what temperature would the wavelength of a 440 Hz sound wave be 0.82 meters?

Equation to find the speed of sound: Vт = Vo √(T/273)

T = 273 + t(°C)

My calculations:

Vт = 440 Hz (0.82 m) = 360.8 m/s

Vт = Vo √(T/273)
360.8 m/s = 331.3 m/s (t^2)
-331.3 m/s = -331.3 m/s (t^2)
29.5 = t^2
√(29.5) = t
5.431 = t
 
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360.8 m/s = 331.3 m/s (t^2)
-331.3 m/s = -331.3 m/s (t^2)

How did you get that?
 
Nvm. I got help from a friend. Thank you for your help though!
 
welcome!
 

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