- #1

- 23

- 0

A QM question that im stuck on:

Consider the addition of the spin of 2 electrons, s1=s2=½. Show

that there are one ms=1; two ms=0 and one ms=-1 states. Show the

4 spin states are given by:

a1a2

b1b2

(1/(sqrt(2)))(a1b2+b1a2)

(1/(sqrt(2)))(a1b2-b1a2)

I've used a and b in place of alpha and beta, which represent the spin up and spin down states.

I can see why there are one ms=1 and one ms=-1 states, and 2 ms=0 states, from adding the values of ms for individual particles, but am not sure on how to proceed to the second part.

Any nudge in the right direction would be great.

Cheers,

Simon.